QuestionLet $g(x)=\sin (2 x)$, for $-\frac{\pi}{2} \leq x \leq \frac{\pi}{2}$. Where does $g$ have critical points?

Studdy Solution
The critical points of $g(x) = \sin(2x)$ on the interval $-\frac{\pi}{2} \leq x \leq \frac{\pi}{2}$ are $x = \frac{\pi}{4}$ and $x = -\frac{\pi}{4}$.