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Math  /  Algebra

QuestionLet f(x)=3x2+7f(x)=3 x^{2}+7 and g(x)=4−9xg(x)=4-9 x. Find (fg)(x)=f(x)g(x)(f g)(x)=f(x) g(x). (fg)(x)=−27x3−63x(f g)(x)=-27 x^{3}-63 x (fg)(x)=−27x3−63x+28(f g)(x)=-27 x^{3}-63 x+28 (fg)(x)=−27x3+12x2−63x+28(f g)(x)=-27 x^{3}+12 x^{2}-63 x+28 (fg)(x)=3x2−9x+28(f g)(x)=3 x^{2}-9 x+28

Studdy Solution
Arrange the polynomial in standard form (descending order of powers of xx):
(fg)(x)=−27x3+12x2−63x+28 (f g)(x) = -27x^3 + 12x^2 - 63x + 28
Solution: (fg)(x)=−27x3+12x2−63x+28 (f g)(x) = -27x^3 + 12x^2 - 63x + 28

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