Math  /  Algebra

QuestionJika fungsi f(x)=2log(x2)4log(2x212xf(x)={ }^{2} \log (x-2)-{ }^{4} \log \left(2 x^{2}-12 x\right. +19)+19) memotong sumbu xx di (x1,0)\left(x_{1}, 0\right) dan (x2,0)\left(x_{2}, 0\right) maka untuk x1<x2x_{1}<x_{2} nilai 2x1x2=2 x_{1}-x_{2}=
A 1 .
B 2 .
C 3 .
D 4 .
E 5 .

Studdy Solution
Jadi, nilai 2x1x2=12x_1 - x_2 = 1.
Jawabannya adalah **A**.

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