Math  /  Data & Statistics

QuestionIs the typical (mean) amount of yards gained different between AFC and NFC teams? A random sample of yards gained for 35 NFC teams and for another sample of 35 AFC teams was recorded.
Based on the scenario described, were independent samples design or dependent samples design used? independent dependent \begin{tabular}{|c|c|c|c|} \hline & Sample Mean & Std. Err. & P-Values \\ \hline AFC-NFC & 6.3 & 19.1 & 0.37,0.63,0.740.37,0.63,0.74 \\ \hline \end{tabular}
Use a significance level of 0.10 when conducting the test. - Select the appropriate hypotheses. Make sure the notation used in the hypotheses agrees with the type of samples selected. Ho:μ1=μ2Ho:μ1=μ2Ho:μd=0Ho:μ1=μ2Ho:μd=0Ho:μd=0Ha:μ1μ2Ha:μ1<μ2Ha:μd<0Ha:μ1>μ2Ha:μd>0Ha:μd0\begin{array}{l} H_{o}: \mu_{1}=\mu_{2} \quad H_{o}: \mu_{1}=\mu_{2} H_{o}: \mu_{d}=0 \quad H_{o}: \mu_{1}=\mu_{2} \quad H_{o}: \mu_{d}=0 \quad H_{o}: \mu_{d}=0 \\ H_{a}: \mu_{1} \neq \mu_{2} \quad H_{a}: \mu_{1}<\mu_{2} \quad H_{a}: \mu_{d}<0 \quad H_{a}: \mu_{1}>\mu_{2} \quad H_{a}: \mu_{d}>0 \quad H_{a}: \mu_{d} \neq 0 \end{array} - α=\alpha= \square reject HoH_{o} if probability ? ( α\alpha - TS:t=\mathrm{TS}: \mathrm{t}= \square (Round to 2 digits after the decimal point.) - probability = \square (Make sure you reference the probabilities in the output.) - decision: Select an answer \square - At the 0.10 level, there Select an answer - significant evidence to conclude the mean yards gained for AFC teams is Select an answer (C) than the mean for NFC teams.

Studdy Solution
Make a decision based on the p-value and significance level (α=0.10\alpha = 0.10):
- Since the p-value (0.370.37) is greater than the significance level (0.100.10), we do not reject the null hypothesis.
Decision: There is no significant evidence to conclude that the mean yards gained for AFC teams is different than the mean for NFC teams at the 0.10 significance level.

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