Math  /  Geometry

QuestionIn triangle DEF,mED E F, m \angle E is three times mDm \angle D, and mFm \angle F is 99^{\circ} less than mEm \angle E. What is the measure of each angle?
Find the m<D=m<D= \square Find the m<E=m<E= \square Find the m<F=\mathrm{m}<\mathrm{F}= \square

Studdy Solution
Verify the solution by checking the sum of the angles:
mD+mE+mF=27+81+72=180 m \angle D + m \angle E + m \angle F = 27^\circ + 81^\circ + 72^\circ = 180^\circ
The sum is correct, confirming the solution.
The measures of the angles are: - mD=27 m \angle D = \boxed{27^\circ} - mE=81 m \angle E = \boxed{81^\circ} - mF=72 m \angle F = \boxed{72^\circ}

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