Math  /  Geometry

QuestionIn triangle ABCABC, with points DD on ABAB and EE on BCBC, find angles given ABC=28\angle ABC=28^{\circ}, BED=38\angle BED=38^{\circ}. (a) Find ACD\angle ACD. (b) Express DFE\angle DFE in terms of θ\theta where CAE=θ\angle CAE=\theta.

Studdy Solution
implify the equation to find DFE\angle DFE.
DFE=180θ142+θ=38\angle DFE =180^{\circ} - \theta -142^{\circ} + \theta =38^{\circ}So, the solutions are ACD=124\angle ACD =124^{\circ} and DFE=38\angle DFE =38^{\circ}.

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