QuestionGiven $AB=36 \mathrm{~cm}, BC=48 \mathrm{~cm}, AD=109 \mathrm{~cm}$, find $AC$, $CD$, and the area of quadrilateral $ABCD$.

Studdy Solution
Add the areas of $\triangle ABC$ and $\triangle ACD$ to find the area of quadrilateral $ABCD$.
$$Area_{ABCD} =864 +2730 =3594 \text{ cm}^2$$So, $AC =60$ cm, $CD =91$ cm, and the area of quadrilateral $ABCD$ is $3594$ cm$^2$.