QuestionFind the value of $x+y+z+w$ given $\angle C = 140^\circ$ and angles $A$, $B$, $D$, $E$ at intersection point $C$.

Studdy Solution
Calculate the value of $x+y+z+w$.
$$x + y + z + w =40 +40 =80$$So, the correct value of $x+y+z+w$ is $80$ degrees. This matches with option A.
The correct answer is A.80.