Math  /  Geometry

Question Find the length of CD and BF given a square ABCD with straight lines AFD, BFE, and CDE, where DF=6cm and EF=10cm.
CD=(6)2+(10)2=100=10 cmC D=\sqrt{(6)^2+(10)^2}=\sqrt{100}=10\mathrm{~cm} BF=(6)2(10)2=4=2 cmB F=\sqrt{(6)^2-(10)^2}=\sqrt{4}=2\mathrm{~cm}

Studdy Solution
Calculate the square root of236.
BF=15.36 cmBF =15.36 \text{ cm}So, CD=11.66CD =11.66 cm and BF=15.36BF =15.36 cm.

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