Math  /  Discrete

QuestionIn a soccer match, a tie at the end of two overtime periods leads to a "shootout" with five kicks taken by each team from the penalty mark. Each kick must be taken by a different player. How many ways can 5 players be selected from the 11 eligible players? For the 5 selected players, how many ways can they be designated as first, second, third, fourth, and fifth? 5 players can be selected from the 11 eligible players in \square \square different ways. Out of those 5 players that are selected, they can be designated as first, second, third, fourth, and fifth in different ways. (Type whole numbers.)

Studdy Solution
Combine the results from STEP_3 and STEP_4:
The total number of ways to first select 5 players from 11 and then designate their order is:
(115)×5!=462×120=55440 \binom{11}{5} \times 5! = 462 \times 120 = 55440
Solution:
There are 462462 ways to select 5 players from the 11 eligible players. Out of those 5 players that are selected, they can be designated as first, second, third, fourth, and fifth in 120120 different ways.
Therefore, the total number of ways to select and designate the players is 5544055440.

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord