Math  /  Algebra

Question(II) How much work would movers do pushing a 46.0kg46.0-\mathrm{kg} crate 10.3 m horizontally across a rough floor without acceleration, if the effective coefficient of friction was 0.40 ?

Studdy Solution
Calculate the work done against the friction force.
The work done W W is given by the formula: W=fd W = f \cdot d
where d=10.3m d = 10.3 \, \text{m} is the distance the crate is pushed.
Substitute the known values: W=180.32N×10.3m W = 180.32 \, \text{N} \times 10.3 \, \text{m}
Calculate the work done: W=1856.296J W = 1856.296 \, \text{J}
The work done by the movers is approximately: 1856.3J \boxed{1856.3 \, \text{J}}

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