Math  /  Algebra

QuestionIf y=(3x+7)xy=(3 x+7)^{x} find y(0)y(0) A. ln(7)\ln (7) B. 0 C. ln(7)+37\ln (7)+\frac{3}{7} D. 7ln(7)+37 \ln (7)+3 E. 7ln(7)377 \ln (7)-\frac{3}{7}
Answer:

Studdy Solution
Recall the property of exponents that any non-zero number raised to the power of 0 is 1:
70=1 7^0 = 1
Therefore, y(0)=1 y(0) = 1 .
The value of y(0) y(0) is:
1 \boxed{1}
None of the provided options (A, B, C, D, E) match the result of y(0)=1 y(0) = 1 . It seems there might be an error in the provided options.

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