Math / CalculusQuestionIf −y3−3−4xy+4x=0-y^{3}-3-4 x y+4 x=0−y3−3−4xy+4x=0 then find dydx\frac{d y}{d x}dxdy in terms of xxx and yyy.Studdy SolutionSo, we found that dydx=4(y−1)−3y2−4x\frac{dy}{dx} = \frac{4(y - 1)}{-3y^2 - 4x}dxdy=−3y2−4x4(y−1).Awesome!View Full Solution - FreeWas this helpful?
