Math / CalculusQuestionFind limx→2f(x)\lim _{x \rightarrow 2} f(x)limx→2f(x) given that limx→2[f(x)]2−8x+3x+1=9\lim _{x \rightarrow 2} \sqrt{\frac{[f(x)]^{2}-8 x+3}{x+1}}=9limx→2x+1[f(x)]2−8x+3=9 and f(x)≥0f(x) \geq 0f(x)≥0.Studdy SolutionCalculate the limit to getlimx→2f(x)=16\lim{x \rightarrow2} f(x)=16limx→2f(x)=16So, limx→2f(x)=16\lim{x \rightarrow2} f(x)=16limx→2f(x)=16. View Full Solution - FreeWas this helpful?
