Math  /  Trigonometry

QuestionIf sint=1019\sin t=-\frac{10}{19} and if the terminal point is in Quadrant III, find tsint+sectt \sin t+\sec t

Studdy Solution
Calculate tsint+sectt \sin t + \sec t:
Since tt is not specified as a numerical value, we assume tsintt \sin t is simply 1019t-\frac{10}{19}t.
tsint+sect=1019t19261t \sin t + \sec t = -\frac{10}{19}t - \frac{19}{\sqrt{261}}
The expression tsint+sectt \sin t + \sec t is:
1019t19261-\frac{10}{19}t - \frac{19}{\sqrt{261}}

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