Math  /  Calculus

QuestionEvaluate Fdr\int F \cdot d r for Fˉ=xyiˉzj+x2kˉ\bar{F}=x y \bar{i}-z j+x^{2} \bar{k} along the curve x=t2x=t^{2}, y=2ty=2t, z=t3z=t^{3} from t=0t=0 to t=1t=1. Answer: 5170\frac{51}{70}.

Studdy Solution
Now, evaluate the integral.
0(4t42t3+3t6)dt=[45t52t4+37t7]0=452+37=5170\int_{0}^{} (4t^{4} -2t^{3} +3t^{6}) dt = \left[\frac{4}{5}t^{5} - \frac{}{2}t^{4} + \frac{3}{7}t^{7}\right]_{0}^{} = \frac{4}{5} - \frac{}{2} + \frac{3}{7} = \frac{51}{70}The value of the line integral of the vector field ˉ\bar{} along the curve cc is 5170\frac{51}{70}.

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