Math  /  Geometry

QuestionIf EC\overline{EC} is an altitude of AED\triangle AED, and AC=CDAC = CD, with m1=2x+7m \angle 1 = 2x + 7 and m2=3x+13m \angle 2 = 3x + 13, find m1m \angle 1 and m2m \angle 2.

Studdy Solution
Calculate m2 m \angle 2 :
m2=3x+13=3(14)+13=42+13=55 m \angle 2 = 3x + 13 = 3(14) + 13 = 42 + 13 = 55^\circ
The measures of the angles are:
m1=35 m \angle 1 = 35^\circ m2=55 m \angle 2 = 55^\circ

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