Math / AlgebraQuestionIf A=[b2−131−1−103]A = \begin{bmatrix} b & 2 & -1 \\ 3 & 1 & -1 \\ -1 & 0 & 3 \end{bmatrix}A=⎣⎡b3−1210−1−13⎦⎤ and [1α1]\begin{bmatrix} 1 \\ \alpha \\ 1 \end{bmatrix}⎣⎡1α1⎦⎤ is an eigenvector of the matrix AAA, then b=b =b=Answer:Studdy SolutionTherefore, b=−1b = -1b=−1.View Full Solution - FreeWas this helpful?