Math  /  Algebra

Question(I) How high will a 1.85kg1.85-\mathrm{kg} rock go if thrown straight up by someone who does 70.0 J of work on it? Neglect air resistance.

Studdy Solution
Solve for the maximum height.
Rearrange the equation to solve for h h :
h=70.01.85×9.81 h = \frac{70.0}{1.85 \times 9.81}
Calculate the value:
h70.018.1485 h \approx \frac{70.0}{18.1485}
h3.86m h \approx 3.86 \, \text{m}
The maximum height the rock will reach is:
3.86m \boxed{3.86 \, \text{m}}

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