Math  /  Discrete

Question(i) AΔ(BΔC)=(AΔB)ΔCA \Delta(B \Delta C)=(A \Delta B) \Delta C (ii) A(BC)c=(AB)(AC)A \cap(B \cup C)^{c}=(A-B) \cup(A-C)

Studdy Solution
(i) The symmetric difference is associative, as our example suggests. (ii) The given statement about set operations is **false**, as demonstrated by our counterexample.
The correct statement should use intersection instead of union on the right-hand side.

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