QuestionHow many moles of $\mathrm{NH}_{3}$ are produced from 4 moles of $\mathrm{H}_{2}$ with excess $\mathrm{N}_{2}$? $$3 \mathrm{H}_{2}+\mathrm{N}_{2} \rightarrow 2 \mathrm{NH}_{3}$$

Studdy Solution
Calculate the value of $x$.
$$x = \frac{2 \times4}{3} = \frac{8}{3} \approx2.67 \, \text{moles}$$So, if complete reaction occurs with4 moles of $\mathrm{H}_{2}$ and excess $\mathrm{}_{2}$, approximately2.67 moles of $\mathrm{NH}_{3}$ will be formed.