Math  /  Word Problems

QuestionHow many mg of a metal with 45% nickel is needed to mix with 6 mg of pure nickel for a 78% nickel alloy?

Studdy Solution
Calculate the value of xx.
x=.320.33=x = \frac{.32}{0.33} =So, mg of a metal containing45% nickel must be combined with6 mg of pure nickel to form an alloy containing78% nickel.

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