QuestionHow many kg of oil are needed to heat 190 kg of water from 28°C to 100°C, given $1 \mathrm{lb}=454 \mathrm{g}$?

Studdy Solution
Calculate the mass of oil needed.
$$m_{\text{oil}} = \frac{Q}{2.6 \times10^{7} \, \mathrm{J/lb} \times \frac{1}{454 \, \mathrm{g/lb}}}$$The mass of oil needed is1270 kg.