Question Sell 21 tickets for a school play, with adult tickets at $6 and child tickets at$ 4. Solve for the number of adult and child tickets sold.
$a$ = number of adult tickets, $c$ = number of child tickets $a + c = 21$ $6a + 4c = 104$

Studdy Solution
Since we have found a solution that satisfies both equations, we can conclude that the number of adult tickets sold is 10 and the number of child tickets sold is 11.
The solution is: \# of adult tickets $= 10$ \# of child tickets $= 11$

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