QuestionGraph the quadratic equation in desmos, then determine if the vertex is a maximum or minimum. * 1 point 5) Maximum or Minimum? $$y=-x^{2}+3 x-4$$ A) Maximum B) Minimum $A$ $B$

Studdy Solution
Graph the quadratic equation $y = -x^2 + 3x - 4$ on Desmos or any graphing utility to visually confirm the vertex is a maximum.
The graph confirms the vertex at $\left( \frac{3}{2}, -\frac{7}{4} \right)$ and shows the parabola opening downwards, indicating the vertex is indeed a maximum.
Solution: The vertex of the quadratic equation $y = -x^2 + 3x - 4$ is a maximum.