QuestionSketch the least positive angle $\theta$ from the line $-7x - 3y = 0$ where $x \leq 0$, and find the six trig functions of $\theta$.

Studdy Solution
Substitute $x = -7$ and $y =$ into the equations to find the values of the six trigonometric functions.
$$r = \sqrt{(-7)^2 +^2} = \sqrt{49 +9} = \sqrt{58}$$$$\sin(\theta) = \frac{}{\sqrt{58}}$$$$\cos(\theta) = \frac{-7}{\sqrt{58}}$$$$\tan(\theta) = \frac{}{-7} = -\frac{7}{}$$$$\csc(\theta) = \frac{\sqrt{58}}{}$$$$\sec(\theta) = \frac{\sqrt{58}}{-7} = -\frac{\sqrt{58}}{7}$$$$\cot(\theta) = -\frac{7}{}$$The least positive angle $\theta$ and the six trigonometric functions of $\theta$ have been found.