QuestionGraph $f(t)=t^{2}+10 t+23$. You ony need to graph the vertext and one other point.

Studdy Solution
Sketch the graph using the vertex and the additional point:
1. Plot the vertex $(-5, -2)$ on the graph.
2. Plot the additional point $(0, 23)$.
3. Draw a smooth curve through these points, ensuring the parabola opens upwards (since $a = 1 > 0$).
The graph of $f(t) = t^2 + 10t + 23$ has its vertex at $(-5, -2)$ and passes through the point $(0, 23)$.