Math  /  Geometry

QuestionFind the value(s) of hh so that the vector b=[49h]b = \left[\begin{array}{r}4 \\ -9 \\ h\end{array}\right] lies in the plane spanned by a1=[131]a_{1} = \left[\begin{array}{r}1 \\ 3 \\ -1\end{array}\right] and a2=[6112]a_{2} = \left[\begin{array}{r}-6 \\ -11 \\ 2\end{array}\right]. The value(s) of hh is(are) \square.

Studdy Solution
Finally, substituting x=14x = -14 and y=3y = -3 into the third equation, we get(14)+2(3)=h-(-14) +2(-3) = h146=h14 -6 = hh=8h =8So, the value of hh for which bb is in the plane spanned by a1a_{1} and a2a_{2} is h=8h =8.

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