Math  /  Algebra

QuestionSolve for xx and yy given Re(z)=0\operatorname{Re}(z)=0 in these equations:
(i) (x,y)(2,3)=(4,7)(x, y)(2,3)=(-4,7)
(ii) (x+3i)2=2yi(x+3 i)^{2}=2 y i
(iii) (x+2yi)2=xi(x+2 y i)^{2}=x i.

Studdy Solution
Therefore, the solutions for the third equation are (x,y)=(0,0)(x, y) = (0,0).

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