Math / AlgebraQuestionGiven that log(2)≈0.3010\log (2) \approx 0.3010log(2)≈0.3010, find the value of the logarithm. log(2)\log (\sqrt{2})log(2) □\square□ Need Help? Watch itStuddy SolutionCalculate the expression:log(2)=0.1505\log(\sqrt{2}) = 0.1505log(2)=0.1505 The value of log(2)\log(\sqrt{2})log(2) is:0.1505\boxed{0.1505}0.1505View Full Solution - FreeWas this helpful?