Math  /  Geometry

QuestionBerechne die gesuchten Längen für die gegebenen Flächeninhalte und Höhen der Dreiecke:
a) A=17,55 cm2,a=7,8 cm,ha=A=17,55 \mathrm{~cm}^{2}, a=7,8 \mathrm{~cm}, h_{a}= ?
b) A=2340 mm2,hb=36 mm,b=A=2340 \mathrm{~mm}^{2}, h_{b}=36 \mathrm{~mm}, b= ?
c) A=18,25 cm2,c=73 mm,hc=A=18,25 \mathrm{~cm}^{2}, c=73 \mathrm{~mm}, h_{c}= ?
d) A=34,1 cm2,ha=62 mm,a=A=34,1 \mathrm{~cm}^{2}, h_{a}=62 \mathrm{~mm}, a= ?

Studdy Solution
Calculate the base aa.
a=2×34.cm26.2cm=11cma = \frac{2 \times34. \, cm^2}{6.2 \, cm} =11 \, cmThe solutions to the problems area) ha=.5cmh_a =.5 \, cm
c) b=130mmb =130 \, mm
b) hc=5cmh_c =5 \, cm
d) a=11cma =11 \, cm

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord