Math / CalculusQuestionf(x)=2x2+1f(x)=2 x^{2}+1f(x)=2x2+1, given that f′(x)=limh→0f(x+h)−f(x)hf^{\prime}(x)=\lim _{h \rightarrow 0} \frac{f(x+h)-f(x)}{h}f′(x)=limh→0hf(x+h)−f(x) then f′(x)=f^{\prime}(x)=f′(x)=Studdy SolutionEvaluate the limit as h→0 h \to 0 h→0:=4x+2(0) = 4x + 2(0) =4x+2(0) =4x = 4x =4x The derivative f′(x) f'(x) f′(x) is:4x \boxed{4x} 4xView Full Solution - FreeWas this helpful?
