Question$$\begin{array}{l} f(x)=3 x+3 \\ g(x)=x^{2}+3 x+2 \\ r(x)=\frac{2 x+1}{x-1} \\ q(x)=\sqrt{x+1} \end{array}$$ $$1 \cdot(g \circ f)(x)=3 x+2$$

Studdy Solution
We observe that the equation $3x^2 + 8x + 6 = 0$ must hold for all $x$ if the given information is correct. However, clearly, this is a quadratic equation that does not hold for all $x$. Thus, we need to re-examine the given conditions, as it appears there might be an inconsistency or mistake in the provided $g(f(x))$ form.
This suggests that either an error was made in the problem statement or a misinterpretation of the provided $g(f(x))$. Therefore, we conclude:
$$(g \circ f)(x) = 3x + 2$$ does not hold true given the functions $g(x)$ and $f(x)$ as stated.