Question$$f(x)=2 x^{2}-8 x+6$$
The quadratic function has a minimum value. The value is $\square$

Studdy Solution
Calculate the minimum value of the function by substituting $x = 2$ back into the function $f(x)$.
$$f(2) = 2(2)^2 - 8(2) + 6$$
$$f(2) = 2 \times 4 - 16 + 6$$
$$f(2) = 8 - 16 + 6$$
$$f(2) = -2$$
The minimum value of the function is $\boxed{-2}$.