Math  /  Algebra

QuestionDetermine if the following functions are odd/even and injective/surjective/bijective:
1. f(x)=cf(x)=c
2. f(x)=xf(x)=x
3. f(x)=x2f(x)=x^{2}
4. f(x)=x3f(x)=x^{3}
5. f(x)=1xf(x)=\frac{1}{x}
6. f(x)=1x2f(x)=\frac{1}{x^{2}}
7. f(x)=x3f(x)=\sqrt[3]{x}
8. f(x)=xf(x)=\sqrt{x}
9. f(x)=xf(x)=|x|

Studdy Solution
For f(x)=xf(x) = |x|, the function is even because f(x)=f(x)f(x) = f(-x) for all xx in the domain of ff. It is not injective but it is surjective for x0x \geq0.

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