Math  /  Data & Statistics

QuestionFrom historical data, 18%18 \% of people work out daily (p=0.18)(p=0.18). In a sample of 15 (n=15)(n=15) people, use the binomial formula or your TI-8314 to determine the probability that exactly 4 (of the fifteen) work out daily.
For a standard normal distribution: a) What is the probability that zz is less than 0.47 ? b) What is the probability that zz is greater than -1.83 ? \qquad c) What is the probability that zz is between -1.29 and 0.64 ? \qquad d) What is the probability that zz is between -1.96 and 1.96 ? \qquad

Studdy Solution
The probability of exactly 4 out of 15 people working out daily is approximately 0.167\textbf{0.167}.
For the standard normal distribution: a) P(z<0.47)0.6808P(z < 0.47) \approx \textbf{0.6808}, b) P(z>1.83)0.9664P(z > -1.83) \approx \textbf{0.9664}, c) P(1.29<z<0.64)0.6404P(-1.29 < z < 0.64) \approx \textbf{0.6404}, and d) P(1.96<z<1.96)0.95P(-1.96 < z < 1.96) \approx \textbf{0.95}.

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