Math  /  Data & Statistics

QuestionFor the wheel pictured on the right, assume that a person spins the pointer and is awarded the amount indicated by the pointer. Determine the person's expectation assuming the spinner has not yet been spun.
What is the expectation? \ \square$ (Simplify your answer. Type an integer or a decimal.)

Studdy Solution
Use the formula for expectation:
E(X)=(value×probability) E(X) = \sum ( \text{value} \times \text{probability} )
Calculate the expected value:
E(X)=10×13+(6)×13+(21)×13 E(X) = 10 \times \frac{1}{3} + (-6) \times \frac{1}{3} + (-21) \times \frac{1}{3}
E(X)=10363213 E(X) = \frac{10}{3} - \frac{6}{3} - \frac{21}{3}
E(X)=106213 E(X) = \frac{10 - 6 - 21}{3}
E(X)=173 E(X) = \frac{-17}{3}
E(X)=5.67 E(X) = -5.67
The expectation is:
5.67 \boxed{-5.67}

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