Math  /  Calculus

QuestionFor the following exercises, use this scenario: A pot of hot soup with an internal temperature of 9696^{\circ} Fahrenheit was taken off the stove to cool in a 74Froom74^{\circ} \mathrm{Froom}. After fifteen minutes, the internal temperature of the soup was 91F91^{\circ} \mathrm{F}. Use Newton's Law of Cooling to write a formula that models this situation. Round to 5 decimal places if necessary T(t)=T(t)=
To the nearest minute, how long will it take the soup to cool to 80F80^{\circ} \mathrm{F} ? \square minutes.
To the nearest degree, what will the temperature be after 2 and a half hours? \qquad F{ }^{\circ} \mathrm{F} Question Help: Written Example Submit Question

Studdy Solution
It will take approximately **78 minutes** for the soup to cool to 8080^\circF.
After 2.5 hours, the temperature will be about 76\boldsymbol{76^\circ}F.

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