Math  /  Geometry

QuestionFind xx given that mBJK=146+2xm \angle BJK = 146 + 2x, mIJK=172m \angle IJK = 172^\circ, and mIJB=2x+26m \angle IJB = 2x + 26.

Studdy Solution
Calculate the value of xx.
x=0x =0So, x=0x =0.

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