Math  /  Algebra

QuestionSolve for θ\theta using the substitution y=9cosθy=9 \cos \theta in the equation 81y2\sqrt{81-y^{2}}.

Studdy Solution
Since θ\theta is in the range of [0,π][0, \pi], sinθ\sin \theta is always positive. So, we can drop the absolute value sign.
9sinθ9 \sin \thetaSo, the simplified form of the given equation 81y2\sqrt{81-y^{2}} using the substitution y=9cosθy=9 \cos \theta is 9sinθ9 \sin \theta.

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