Question Find the $x$-value that separates the top 12% of a normal distribution with $\mu=52.1, \sigma=7.5$ from the rest of the data.

Studdy Solution
Add the values to find $x$:
$$x = 60.9125$$
The $x$-value that separates the top $12\%$ of the data from the rest in a normal distribution with $\mu = 52.1$ and $\sigma = 7.5$ is approximately $60.91$.