Question Find the roots of the quadratic equation $2x^2 - x - 28 = 0$ by factoring.

Studdy Solution
olve these two equations to find the zeros.
For $2x +7 =0$, subtract $7$ from both sides and then divide by $2$ to get $x = -\frac{7}{2}$.
For $x -4 =0$, add $4$ to both sides to get $x =4$.
So, the zeros of the function $f(x)=2x^2-x-28$ are $x = -\frac{7}{2}$ and $x =4$.