Math  /  Geometry

QuestionFind the values of xx and yy in parallelogram PQRSP Q R S PT=y,TR=2x+1,QT=5y,TS=6x+13P T=y, T R=2 x+1, Q T=5 y, T S=6 x+13 x=x= \square and y=y= \square

Studdy Solution
Solve the system of equations for xx and yy.
First, solve the first equation for yy:
y=2x+1 y = 2x + 1
Substitute this expression for yy into the second equation:
5(2x+1)=6x+13 5(2x + 1) = 6x + 13
Simplify and solve for xx:
10x+5=6x+13 10x + 5 = 6x + 13 10x6x=135 10x - 6x = 13 - 5 4x=8 4x = 8 x=2 x = 2
Now, substitute x=2x = 2 back into the equation for yy:
y=2(2)+1 y = 2(2) + 1 y=4+1 y = 4 + 1 y=5 y = 5
The values are:
x=2 x = \boxed{2} y=5 y = \boxed{5}

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord