Math / AlgebraQuestionSolve the equation: log8x2=4\log_{8} x^{2} = 4log8x2=4.Studdy SolutionCalculate the square root of409.x=±64x = \pm64x=±64So, the solutions to the equation log8x2=4\log{8} x^{2}=4log8x2=4 are x=64x =64x=64 and x=−64x = -64x=−64. View Full Solution - FreeWas this helpful?