QuestionConvert the quadratic equation $3x^{2}+3y^{2}-9x+15y=21$ to standard form.

Studdy Solution
Finally, divide both sides of the equation by $3$ to get the standard form of the given quadratic equation.
$$(x-\frac{3}{2})^{2}+(y+\frac{5}{2})^{2}=14$$So, the standard form of the given quadratic equation is $(x-\frac{3}{2})^{2}+(y+\frac{5}{2})^{2}=14$.