QuestionRewrite the equation $y^{2}-x^{2}+4 x+2 y-5=0$ in standard form.

Studdy Solution
Finally, we rewrite the equation in the standard form $A(x-h)^{2} + B(y-k)^{2} =1$.
$$\frac{(x-2)^{2}}{10}-\frac{(y+1)^{2}}{10}=1$$The standard form of the equation $y^{2}-x^{2}+4 x+2 y-5=0$ is $\frac{(x-2)^{2}}{10}-\frac{(y+1)^{2}}{10}=1$.