Math  /  Geometry

QuestionFind the perimeter and area of the figure pictured below.
Perimeter == \square m
Area == \square m2\mathrm{m}^{2}

Studdy Solution
Calculate the area of each simpler shape and sum them up:
- Area of Rectangle 1:
Area1=9m×2m=18m2 \text{Area}_1 = 9 \, \text{m} \times 2 \, \text{m} = 18 \, \text{m}^2
- Area of Rectangle 2:
Area2=5m×10m=50m2 \text{Area}_2 = 5 \, \text{m} \times 10 \, \text{m} = 50 \, \text{m}^2
- Total Area:
Total Area=Area1+Area2=18m2+50m2=68m2 \text{Total Area} = \text{Area}_1 + \text{Area}_2 = 18 \, \text{m}^2 + 50 \, \text{m}^2 = 68 \, \text{m}^2
The perimeter of the figure is:
42m \boxed{42 \, \text{m}}
The area of the figure is:
68m2 \boxed{68 \, \text{m}^2}

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