QuestionFind the partial fraction decomposition. $$\frac{10 x-14}{(x-2)(2 x-3)}=$$ $\square$

Studdy Solution
Write the final partial fraction decomposition using the values of $A$ and $B$. $$\frac{10x - 14}{(x-2)(2x-3)} = \frac{6}{x-2} + \frac{-2}{2x-3}$$ Or equivalently: $$\frac{10x - 14}{(x-2)(2x-3)} = \frac{6}{x-2} - \frac{2}{2x-3}$$