Studdy AI Logo
Math  /  Calculus

QuestionSubmit Answer
6. [-/1 Points]
DETAILS MY NOTES SCALCET9 4.9.021.
Find the most general antiderivative of the function. (Check your answer by differentiation. Use CC for the constant of the antiderivative.) f(θ)=4sin⁡(θ)−9sec⁡(θ)tan⁡(θ)f(\theta)=4 \sin (\theta)-9 \sec (\theta) \tan (\theta) \quad on the interval (−π2,π2)\left(-\frac{\pi}{2}, \frac{\pi}{2}\right) F(θ)=F(\theta)= □\square
Need Help? Read it □\square Submit Answer

Studdy Solution
Include the constant of integration C C in the final answer:
The most general antiderivative is:
F(θ)=−4cos⁡(θ)−9sec⁡(θ)+C F(\theta) = -4 \cos(\theta) - 9 \sec(\theta) + C
The most general antiderivative is:
−4cos⁡(θ)−9sec⁡(θ)+C \boxed{-4 \cos(\theta) - 9 \sec(\theta) + C}

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord