Math  /  Algebra

QuestionFind the logarithm. log100.1\log _{10} 0.1

Studdy Solution
Apply the logarithm property logb(ba)=a\log_{b}(b^a) = a, where bb is the base of the logarithm and aa is the exponent:
log10(0.1)=log10(101) \log_{10}(0.1) = \log_{10}(10^{-1})
Using the property:
log10(101)=1 \log_{10}(10^{-1}) = -1
The value of the logarithm is:
1 \boxed{-1}

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